72v^2+30v-7=0

Solution for 72v^2+30v-7=0 equation:

72v^2+30v-7=0

a = 72; b = 30; c = -7;
Δ = b2-4ac
Δ = 302-4·72·(-7)
Δ = 2916
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2916}=54$
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(30)-54}{2*72}=\frac{-84}{144}
=-7/12
$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(30)+54}{2*72}=\frac{24}{144}
=1/6
$